记录详情 - QLUOJ

#	状态分数	耗时	内存占用
#1	Wrong Answer 0 User output longer than standard answer.	2ms	376 KiB
#2	Wrong Answer 0 User output longer than standard answer.	3ms	632 KiB
#3	Wrong Answer 0 读取到 a，应为 not。	2ms	504 KiB
#4	Wrong Answer 0 读取到 prime.This，应为 prime.。	3ms	760 KiB
#5	Wrong Answer 0 User output longer than standard answer.	2ms	632 KiB
#6	Wrong Answer 0 读取到 a，应为 not。	2ms	644 KiB
#7	Wrong Answer 0 读取到 a，应为 not。	2ms	504 KiB
#8	Wrong Answer 0 读取到 a，应为 not。	3ms	888 KiB
#9	Wrong Answer 0 读取到 a，应为 not。	2ms	760 KiB
#10	Wrong Answer 0 读取到 a，应为 not。	3ms	760 KiB
#11	Wrong Answer 0 User output longer than standard answer.	2ms	376 KiB
#12	Wrong Answer 0 User output longer than standard answer.	4ms	760 KiB
#13	Wrong Answer 0 User output longer than standard answer.	3ms	760 KiB
#14	Wrong Answer 0 User output longer than standard answer.	2ms	632 KiB
#15	Wrong Answer 0 User output longer than standard answer.	2ms	504 KiB
#16	Wrong Answer 0 User output longer than standard answer.	2ms	380 KiB
#17	Wrong Answer 0 User output longer than standard answer.	2ms	376 KiB
#18	Wrong Answer 0 读取到 a，应为 not。	2ms	504 KiB
#19	Wrong Answer 0 User output longer than standard answer.	2ms	376 KiB
#20	Wrong Answer 0 读取到 prime.This，应为 prime.。	2ms	376 KiB
#21	Wrong Answer 0 User output longer than standard answer.	3ms	888 KiB
#22	Wrong Answer 0 读取到 a，应为 not。	2ms	632 KiB
#23	Wrong Answer 0 读取到 a，应为 not。	2ms	376 KiB
#24	Wrong Answer 0 User output longer than standard answer.	2ms	376 KiB
#25	Wrong Answer 0 读取到 prime.This，应为 prime.。	2ms	376 KiB
#26	Wrong Answer 0 读取到 a，应为 not。	3ms	504 KiB
#27	Wrong Answer 0 User output longer than standard answer.	2ms	632 KiB
#28	Wrong Answer 0 读取到 a，应为 not。	2ms	632 KiB
#29	Wrong Answer 0 读取到 a，应为 not。	3ms	632 KiB
#30	Wrong Answer 0 User output longer than standard answer.	3ms	632 KiB

递交者: 刘鑫雨 LV 7
题目: P1318 判断素数（循环结构）
语言: C++17(O2)
递交时间: 2024-8-6 17:11:16
评测时间: 2024-8-6 17:11:17

分数: 0
总耗时: 70ms
峰值时间: 4ms
峰值内存: 888 KiB

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