记录详情 - QLUOJ

#	状态分数	耗时	内存占用
#1	Wrong Answer 0 Standard answer longer than user output.	1ms	248 KiB
#2	Wrong Answer 0 Standard answer longer than user output.	1ms	248 KiB
#3	Wrong Answer 0 读取到 a，应为 not。	1ms	248 KiB
#4	Wrong Answer 0 读取到 prime，应为 prime.。	1ms	248 KiB
#5	Wrong Answer 0 Standard answer longer than user output.	1ms	248 KiB
#6	Wrong Answer 0 读取到 a，应为 not。	1ms	248 KiB
#7	Wrong Answer 0 读取到 a，应为 not。	1ms	248 KiB
#8	Wrong Answer 0 读取到 a，应为 not。	1ms	260 KiB
#9	Wrong Answer 0 读取到 a，应为 not。	1ms	248 KiB
#10	Wrong Answer 0 读取到 a，应为 not。	1ms	248 KiB
#11	Wrong Answer 0 Standard answer longer than user output.	1ms	248 KiB
#12	Wrong Answer 0 Standard answer longer than user output.	1ms	248 KiB
#13	Wrong Answer 0 Standard answer longer than user output.	1ms	376 KiB
#14	Wrong Answer 0 Standard answer longer than user output.	1ms	248 KiB
#15	Wrong Answer 0 Standard answer longer than user output.	1ms	248 KiB
#16	Wrong Answer 0 Standard answer longer than user output.	1ms	252 KiB
#17	Wrong Answer 0 Standard answer longer than user output.	1ms	248 KiB
#18	Wrong Answer 0 读取到 a，应为 not。	1ms	368 KiB
#19	Wrong Answer 0 Standard answer longer than user output.	1ms	248 KiB
#20	Wrong Answer 0 读取到 prime，应为 prime.。	1ms	252 KiB
#21	Wrong Answer 0 Standard answer longer than user output.	1ms	248 KiB
#22	Wrong Answer 0 读取到 a，应为 not。	1ms	248 KiB
#23	Wrong Answer 0 读取到 a，应为 not。	1ms	248 KiB
#24	Wrong Answer 0 Standard answer longer than user output.	1ms	252 KiB
#25	Wrong Answer 0 读取到 prime，应为 prime.。	1ms	248 KiB
#26	Wrong Answer 0 读取到 a，应为 not。	1ms	248 KiB
#27	Wrong Answer 0 Standard answer longer than user output.	1ms	248 KiB
#28	Wrong Answer 0 读取到 a，应为 not。	1ms	248 KiB
#29	Wrong Answer 0 读取到 a，应为 not。	1ms	248 KiB
#30	Wrong Answer 0 Standard answer longer than user output.	1ms	252 KiB

递交者: zyc Weekly_Expert LV 8
题目: P1318 判断素数（循环结构）
语言: C
递交时间: 2024-9-29 14:56:03
评测时间: 2024-9-29 14:56:04

分数: 0
总耗时: 23ms
峰值时间: 1ms
峰值内存: 376 KiB

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